1. The average age of three boys is 15 years. If their ages are in ratio 3:5:7, the age of the youngest boy is
A. 21 years
B. 18 years
C. 15 years
D. 9 years (Answer)
E. 12 years
Answer: Option D
Solution: Sum of ages of three boys = 45 years
Now, (3x+5x+7x) = 45
Or, 15x = 45
Or, x = 3
So, age of youngest boy = 3x = 3*3 = 9 years.
2. Find the average of first 97 natural numbers.
A. 47
B. 37
C. 48
D. 49 (Answer)
E. 49.5
Answer: Option D
Solution: 1st Method:
Average of 1st n natural number is given by = ([n*(n+1)]/2)/n
Average of 1st 97 natural number is given by = {([97*(97+1)]/2)/97} = 49
2nd Method:
These numbers are in AP series, so average,
= (sum of corresponding term)/2
= (1+97)/2 = 49
Or, (2+96)/2 = 49
Or, (3+95)/2 = 49 And so on.
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3. Average cost of 5 apples and 4 mangoes is Rs. 36. The average cost of 7 apples and 8 mangoes is Rs. 48. Find the total
cost of 24 apples and 24 mangoes.
A. 1044
B. 2088 (Answer)
C. 720
D. 3240
Answer: Option B
Solution: Average cost of 5 apples and 4 mangoes = Rs. 36.
Total cost = 36 * 9 = 324.
Average cost of 7 apples and 8 mangoes = 48.
Total cost = 48 * 15 = 720.
Total cost of 12 apples and 12 mangoes = 324 + 720 = 1044.
Therefore, cost of 24 apples and 24 mangoes = 1044 * 2 = 2088.
4. The average of a group of men is increased by 5 years when a person aged of 18 years is replaced by a new person of
aged 38 years. How many men are there in the group?
A. 3
B. 4 (Answer)
C. 5
D. 6
E. 7
Answer: Option B
Solution: Let N be the no. of persons in the group.
Required number of person is given by;
Member in group* aged increased = difference of replacement
N*5 = 38-18
Or, 5N = 20
Or, N = 4.
5. Ali has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8
runs. His new average is:
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A. 20
B. 21
C. 28 (Answer)
D. 32
Answer: Option C
Solution: Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x+8)*10 runs in 10 innings.
Now,
=>9x+100 = 10*(x+8)
Or, 9x+100 = 10x+80
Or, x = 100-80
Or, x = 20
New average = (x+8) = 28 runs.
6. The speed of the train going from Nagpur to Allahabad is 100 km/h while when coming back from Allahabad to
Nagpur, its speed is 150 km/h. find the average speed during whole journey.
A. 125 km/hr
B. 75 km/hr
C. 135 km/hr
D. 120 km/hr (Answer)
Answer: Option D
Solution: Average speed,
= (2*x*y)/(x+y)
= (2*100*150)/(100+150)
= (200*150)/250
= 120 km/hr.
7. The average of the first five multiples of 9 is:
A. 20
B. 27 (Answer)
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C. 28
D. 30
Answer: Option B
Solution: Required average = (total sum of multiple of 9)/5
= (9+18+27+36+45)/5
= 27
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.
8. In a boat there are 8 men whose average weight is increased by 1 kg when 1 man of 60 kg is replaced by a new man.
What is weight of new comer?
A. 70
B. 66
C. 68 (Answer)
D. 69
Answer: Option C
Solution: Member in group * age increased = difference of replacement
Or, 8*1 = new comer - man going out
Or, new comer = 8+60;
Or, new comer = 68 years.
9. The average temperature for Wednesday, Thursday and Friday was 40oC. The average for Thursday, Friday and
Saturday was 41oC. If temperature on Saturday was 42oC, what was the temperature on Wednesday?
A. 39oC (Answer)
B. 44oC
C. 38oC
D. 41oC
Solution: Average temperature for Wednesday, Thursday and Friday = 40oC
Total temperature = 3*40 = 120oC
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Average temperature for Thursday, Friday and Saturday = 41oC
Total temperature = 41*3 = 123oC
Temperature on Saturday = 42oC
Now,
(Thursday + Friday + Saturday) - (Wednesday + Thursday + Friday) = 123-120;
Saturday - Wednesday = 3
Wednesday = 42-3 = 39oC.
10. A train covers the first 16 km at a speed of 20 km per hour another 20 km at 40 km per hour and the last 10 km at 15
km per hour. Find the average speed for the entire journey.
A. 24 km
B. 26 km
C. 21 km
D. 23(23/59) km (Answer)
Answer: Option D
Solution: Average speed = total distance covered/ total time
Total distance = (16+40+10) = 46 km
Time taken = (16/20)+ (20/40)+ (10/15) = 59/30
Average speed = 46*30/59 = 23(23/59) km/hr.
11. The average of 25 results is 18. The average of first 12 of those is 14 and the average of last 12 is 17. What is the 13th
result?
A. 74
B. 75
C. 69
D. 78 (Answer)
Answer: Option D
Solution: Sum of 1st 12 results = 12*14
Sum of last 12 results = 12*17
13th result = x (let)
Now,
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12*14+12*17+x = 25*18
Or, x = 78.
12. Which one of the following numbers can be removed from the set S = {0, 2, 4, 5, 9} without changing the average of
set S?
A. 0
B. 2
C. 4 (Answer)
D. 5
Answer: Option C
Solution: The average of the elements in the original set S is: (0+2+4+5+9) /5 =20 /5 =4.
If we remove an element that equals the average, then the average of the new set will remain unchanged. The new set
after removing 4 is {0, 2, 5, 9}.
The average of the elements is,
(0+2+5+9) /4=16 /4 =4.
13. The average marks of four subjects is 120. If 33 was misread as 13 during the calculation, what will be the correct
average?
A. 122
B. 120
C. 125 (Answer)
D. 121
Answer: Option C
Solution: Correct average = 120 + ((33-13)/4) = 120 + 5 = 125
Solve while reading Method:
Average given is 120. Difference of 33 and 13 is 20. That means 20 must be added to total. Then average of 20 is 5 and
so 5 must be added to average i.e. correct average = 120+5 = 125.
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14. The average weight of three boys A, B and C is 163/3 kg, while the average weight of three boys B, D and E is 53 kg.
What is the average weight of A, B, C, D and E?
A. 52.4 kg
B. 53.2 kg
C. 53.8 kg
D. Data inadequate (Answer)
Answer: Option D
Solution: In this question, sum of numbers is provided, net required sum (i.e. A + B+ C+ D + E) cannot be calculated by
the given data.
Therefore the answer is Data inadequate.
15. The average monthly salary of 660 workers in a factory is Rs. 380. The average monthly salary of officers is Rs. 2100
and the average monthly salary of the other workers is Rs. 340. Find the number of other workers.
A. 645 (Answer)
B. 650
C. 640
D. 642
Solution: Total salary of 660 workers = 660*380 = Rs. 250800;
If other workers be x; then,
[(660-x)*2100]+340x = 250800
Or, 1386000-2100x+340x = 250800
1760x = 1135200
Hence, x = 1135200/1760 = 645
Number of other workers = 645.
16. The average age of a family of 5 members is 20 years. If the age of the youngest member be 10 years then what was
the average age of the family at the time of the birth of the youngest member?
A. 13.5
B. 14
C. 15
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D. 12.5 (Answer)
Answer: Option D
Solution: At present the total age of the family = 5*20 =100.
The total age of the family at the time of the birth of the youngest member,
=*100−10−(10*4)+=50.
Therefore, average age of the family at the time of birth of the youngest member,
= 50/4 = 12.5.
17. A man travels equal distances of his journey at 40, 30 and 15 km/h. respectively. Find his average speed for whole
journey.
A. 24
B. 25
C. 27
D. 28
Solution: Required average speed,
= [(3*40*30*15)/{(40*30)+(40*15)+(30*15)}]
= 24 km/hr. Alternatively, Time taken to traveled 1/3 distance of journey with speed 40 kmph, = (1/3)/40 = 1/120. Time
taken to traveled 1/3 distance of journey with speed 30 kmph, = (1/3)/30 = 1/90. Time taken to traveled 1/3 distance of
journey with speed 15 kmph, = (1/3)/15 = 1/45. Total time Taken = (1/120) + (1/90) + (1/45) = 45/1080. Average speed =
Total distance traveled /total time taken = 1/(45/1080) = 24 kmph.
18. Find the average increase rate, if increase in the population in the first year is 30% and that in the second year is
40%.
A. 41 (Answer)
B. 56
C. 40
D. 38
E. 39
Solution: Let 100 be the original population.
1st year's population increased = 30%
So, Population after first year = (100 +30% of 100) = 130. Population in second year increases by 40%, then Population
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= (130 +40% of 130) = 182.
The final population become 182 which was originally at 100. It means there is 82% increment in the population in 2
years
So, Average increment = 82/2 = 41%.
Mind Calculation Method:
Increase in population is given by,
100==30%↑==>130==40%↑==> 182.
Hence, average increase = 82/2 = 41%
19. Average of ten positive numbers is x. If each number is increased by 10%, then x :
A. remains unchanged
B. may decrease
C. may increase
D. is increased by 10% (Answer)
Answer: Option D
Solution: Let 10 numbers be x1, x2, x3 . . . . x10.
According to question average of these 10 numbers is 10.
=> (x1 + x2 + x3 + . . . . + x10)/10 = x
Now if each number is increased by 10%, then new average, say y,
y = (1.1 x1 + 1.1 x2 + 1.1 x3 + . . . . . + 1.1 x10)/10
=> y = 1.1 * ({x1 + x2 + x3 + . . . . . + x10}/10)
=> y= 1.1 x
=> y is 10% increased.
20. Students of three different classes appeared in common examination. Pass average of 10 students of first class was
70%, pass average of 15 students of second class was 60% and pass average of 25 students of third class was 80% then
what will be the pass average of all students of three classes?
A. 74%
B. 75%
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C. 69%
D. 72% (Answer)
Answer: Option D
Solution:
Sum of pass students of first, second and third class,
= (70% of 10) + (60% of 15)+ (80% of 25)
= 7+9+20 = 36
Total students appeared,
= 10+15+25 = 50
Pass average,
= 36*100/50 = 72%.
21. There are five boxes in cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20%
higher than the weight of the third box, whose weight is 25% higher than the first box's weight. The fourth box at 350 kg
is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and the four
lightest boxes.
A. 51.5 kg
B. 75 kg (Answer)
C. 37.5 kg
D. 112.5 kg
E. None of these
Answer: Option B
Solution: The weight of boxes is;
1st box = 200 kg;
3rd box = 250 kg;
2nd box = 300kg;
4th box = 350 kg;
5th box = 500 kg.
Hence, difference between heavier 4 and lighter 4 is 300.
Hence, difference in average is 75.
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22. Average of 80 numbers are 42. When 5 more numbers are included, the average of 85 numbers become 45. Find the
average of 5 numbers.
A. 82
B. 89
C. 93 (Answer)
D. 98
Answer: Option C
Solution: Total of 80 numbers = 80*42 = 3360;
Now, total of 85 numbers = 85*45 = 3825;
Hence, sum of 5 numbers = 3825-3360 = 465;
Average of five numbers = 465/5 = 93.
Solve while reading Method:
Average of 80 number was 42, when 5 more numbers are added average become 45, that means 3 is given to each
number to make their average 45 and 5 numbers also keep 45 as to maintain the entire average.
So, the sum of five numbers = 240+225 = 465,
Hence, average of five numbers = 93.
23. One-fourth of certain journey is covered at the rate of 25 km/h, one-third at the rate of 30 km/h and the rest at 50
km/h. Find the average speed for the whole journey.
A. 600/53km/h
B. 1200/53 km/h
C. 1800/53 km/h (Answer)
D. 1600/53 km/h
E. None of these
Answer: Option C
Solution: Let distance be 120 KM, hence 30 KM is covered by @ 25 kmph and 40 km covered by @ 30 kmph and rest 50
km has been covered@ 50 km.
Now, average = (120/total time taken);
= {120/[(30/25)+(40/30)+(50/50)}]
= 3600/106 = 1800/53 km/h.
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24. A batsman makes a score of 270 runs in the 87th inning and thus increase his average by a certain
number of runs
that is a whole number. Find the possible values of the new average.
A. 98
B. 184
C. 12
D. All of these (Answer)
E. None of these
Answer: Option D
Solution: Part of the runs scored in the 87th innings will go towards increasing the average of the first 86 innings to the
new average and remaining part of the runs will go towards maintaining the new average for the 87th innings. The only
constraint in this problem is that there is increase in average by a whole number of runs. This is possible for all three
options.
25. Five years ago, the average age of A, B, C and D was 45 yr. with E joining them now, the average of all the five is 49
yr. How old is E?
A. 25 yr
B. 40 yr
C. 45yr (Answer)
D. 64 yr
Answer: Option C
Solution:
Total present age of A, B, C and D,
= (45*4)+(4*5) = 200 yr;
Total age present age of A, B, C, D and E,
= 49*5 = 245 yr.
So, age of E = 45 yr.
=================================================
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1. Distance between two stations A and B is 778km. A train covers the journey from A to B at 84km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of train during the whole journey.
A. 60 km/hr
B. 30.5 km/hr
C. 57 km/hr
D. 67.2 km/hr (Answer)
Answer: Option D
Solution: Average speed =[2xy /(x+y)]km/hr.
=[(2*84*56) /(84+56)] km/hr.
=[(2*84*56)/140] km/hr.
= 67.2km/hr.
2. The average wages of a worker during a fortnight comprising 15 consecutive working days was Rs.90 per day. During
the first 7 days, his average wages was Rs.87/day and the average wages during the last 7 days was Rs.92 /day. What
was his wage on the 8th day?
A. 83
B. 92
C. 90
D. 97 (Answer)
Answer: Option D
Solution: The total wages earned during the 15 days that the worker worked ,
= 15 * 90 = Rs. 1350.
The total wages earned during the first 7 days = 7 * 87 = Rs. 609.
The total wages earned during the last 7 days = 7 * 92 = Rs. 644.
Total wages earned during the 15 days,
= wages during first 7 days + wage on 8th day + wages during the last 7 days.
1350 = 609 + wage on 8th day + 644.
wage on 8th day = 1350 - 609 - 644 = Rs. 97.
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3. Ajmal working in a Cellular company as a salesman. His monthly salary is Rs. 200. But he gets bonus as per given rule.
If he sells sim cards of Rs. X then his bonus will be [(x /100)2 +10]. In the first quarter of the year his average sale was Rs.
3000 per month. In the next 5 five month his average sale was Rs. 5000 per month and for next four month his average
sale was Rs. 8000 per month. What is the average earning per month for the whole year?
A. Rs. 3350
B. Rs. 3610 (Answer)
C. Rs. 3750
D. Rs. 3560
E. None of these
Answer: Option B
Solution: Bonus for the first three month,
= [(3000 /100)2 +10] *3
= Rs. 2710.
Bonus for the next five month,
= [(5000 /100)2 +10] *5
= Rs. 12550.
Bonus for the next four month,
= [(8000 /100)2 +10] *4
= Rs. 25640.
Total earning as bonus for whole year,
= 2710 + 12550 +25640
= Rs. 40900.
His average bonus = 40900 /12 = Rs. 3410
Thus his average earning for whole year,
= 3410 + 200
= Rs 3610.
4. David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, mathematics, physics, chemistry and biology. What
are his average marks?
A. 65
B. 69
C. 75 (Answer)
D. None of these
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Answer: Option C
Solution: Average= (76+65+82+67+85)/5 =375/5 =75.
Hence, average =75.
5. The pass percentage of these classes are 20%, 30%, 60% and 100% respectively. Find the pass % of the entire school.
A. 56%
B. 76%
C. 34%
D. 66% (Answer)
E. None of these
Answer: Option D
Solution: The number of pass candidates are 2+6+18+40 = 66 out of total 100.
Hence,
Pass pecentage = 66%.
6. The average of runs of a cricket player of 10 innings was 32. How many runes must be made in his next innings so as
to increase his average of runs by 4?
A. 72
B. 74
C. 70
D. 76 (Answer)
Answer: Option D
Solution: Average after 11 innings = 36.
Required number of runs = ( 36 * 11) - (32 * 10).
=396 -320.
=76.
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7. The average wages of a worker during a fortnight comprising 15 consecutive working days was Rs.90 per day. During
the first 7 days, his average wages was Rs.87/day and the average wages during the last 7 days was Rs.92 /day. What
was his wage on the 8th day?
A. 93
B. 90
C. 92
D. 97 (Answer)
Answer: Option D
Solution: The total wages earned during the 15 days that the worker worked ,
= 15 * 90 = Rs. 1350.
The total wages earned during the first 7 days = 7 * 87 = Rs. 609.
The total wages earned during the last 7 days = 7 * 92 = Rs. 644.
Total wages earned during the 15 days,
= wages during first 7 days + wage on 8th day + wages during the last 7 days.
1350 = 609 + wage on 8th day + 644.
wage on 8th day = 1350 - 609 - 644 = Rs. 97.A school has only four classes that contain 10, 20, 30 and 40 students
respectively.
8. 19 people went to a hotel for combine dinner party 13 of them spent Rs. 79 each on their dinner and rest spent 4
more than the average expenditure of all the 19. What was the total money spent by them.
A. 1628
B. 1534
C. 1492
D. 1496
E. None of these (Answer)
Answer: Option E
Solution: Let average expenditure of 19 people be x.
then,
19x = 13*79+6*(x+4);
Or, 19x = 13*79+6x+24;
Or, x = 80.84;
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So, total money spent = 80.84*19 = Rs. 1536.07.
9. When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g.
What is the average weight of the remaining 59 students?
A. 57 (Answer)
B. 56.8
C. 58.2
D. 52.2
Solution: Let the average weight of the 59 students be X. Therefore, the total weight of the 59 of them will be 59X.
The questions states that when the weight of this student who left is added, the total weight of the class = 59X + 45.
When this student is also included, the average weight decreases by 0.2 kgs.
59X + 45/ 60 = X - 0.2
=> 59X + 45 = 60X - 12
=> 45 + 12 = 60X - 59A
=> X = 57.
10. David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, mathematics, physics, chemistry and biology.
What are his average marks?
A. 65
B. 69
C. 75 (Answer)
D. None of these
Answer: Option C
Solution: Average = (76+65+82+67+85) /5 =375 /5 =75.
Hence, average=75
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11. A passenger travels from Delhi to Merut at a speed of 30 kmph and return with a speed of 60 kmph. What is the
average speed?
A. 40
B. 45 (Answer)
C. 50
D. 48
Solution: Average Speed = [(2*60*30)/(60+30)] = 40 kmph.
The average of 20 students is 12 years, if the teacher's age is included, average increases by one. The age of the teacher
is:
A. 30 yrs
B. 33 yrs
C. 28 yrs
D. 35 yrs
Answer: Option B
Solution: Average of 20 students = 12 years.
Total age of 20 students = 20*12 = 240 years.
When teacher included average become 13 years.
Now, total age 20 students and teacher = 13*21 = 273 years.
Age of teacher = 273-240 = 33 years.
12. The difference between two angles of a triangle is 24o. The average of the same two angles is 54o. Which one of the
following is the value of the greatest angle of the triangle?
A. 45o
B. 60o
C. 66o
D. 72o (Answer)
Answer: Option D
Solution: Let a and b be the two angles in the question, with a > b. We are given that the difference between the angles
is 24o.
=> a – b = 24.
Since the average of the two angles is 54o, we have (a+b)/2 =54.
Solving for b in the first equation yields b=a–24, and substituting this into the second equation yields,
*,a+(a−24)-/2+ =54
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2a−24 = 54*2
2a−24 = 108
2a = 108 +24
2a =132
a =66
Also,
b=a−24=66−24=42.
Now, let c be the third angle of the triangle. Since the sum of the angles in the triangle is
180o, a+b+c =180.
Putting the previous results into the equation yields 66+42+c =180.
Solving for c yields c =72
13. The average income of A, B and C is Rs. 12,000 per month and average income of B, C and D is Rs. 15,000 per month.
If the average salary of D be twice that of A, then the average salary of B and C is in Rs. :
A. 8,000
B. 18,000
C. 13,500 (Answer)
D. 9,000
Answer: Option C
Solution: A+B+C = 12000*3
B+C+D = 15000*3
→ D-A = 3000*3 = 9000
Also, D = 2A
Then, D = 18000 and A = 9000
Therefore,
Average salary of B and C,
= (45000-18000)/2 = 13,500.
14. The average temperature on Wednesday, Thursday and Friday was 20o. The average temperature on Thursday,
Friday and Saturday was 24o. If the temperature on Saturday was 27o, what was the temperature on Wednesday?
A. 24o
B. 21o
C. 27o
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D. 30o (Answer)
Answer: Option D
Solution: Total temperature on Wednesday, Thursday and Friday was 25*3 =75o.
Total temperature on Thursday, Friday and Saturday was 24*3=72o.
Hence, difference between the temperature on Wednesday and Saturday =3o.
If Saturday temperature =27o, then
Wednesday's temperature = 27+3=30o.
15. The average of runs of a cricket player of 10 innings was 32. How many runes must be made in his next innings so as
to increase his average of runs by 4?
A. 72
B. 74
C. 70
D. 76 (Answer)
Answer: Option D
Solution: Average after 11 innings = 36.
Required number of runs,
= ( 36 * 11) - (32 * 10)
= 396-320.
= 76.
16. Nine persons went to a hotel for taking their meals. Eight of them spent Rs.12 each on their meals and the ninth
spent Rs.8 more than the average expenditure of all the nine. What was the total money spent by them.
A. Rs. 115
B. Rs. 116
C. Rs. 117 (Answer)
D. Rs. 118
Answer: Option C
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Solution: Let the average expenditure of all the nine be x.
Then, 12 * 8 + (x + 8) = 9x.
Therefore, x = 13.
Total money spent,
= 9x = Rs.(9 * 13) = Rs.117
17. Therefore average weight = 37.A has 50 coins of 10 paise denominations. While B has 10 coins of 50 paise
denominations. C has 20 coins of 25 paise denominations while D has 25 coins of 20 paise denominations. The average
number of paise per person is:
A. 450 paise
B. 500 paise (Answer)
C. 550 paise
D. 650 paise
Answer: Option B
Solution: [(10 *50) + (50 *10) + (20*25) + (25 *20)] / 4 = 500.
18. The average of 50 numbers is 30. If two numbers, 35 and 40 are discarded, then the average of the remaining
numbers is nearly:
A. 28.32
B. 29.68
C. 28.78
D. 29.27
Answer: Option B
Solution: Total sum of 48 numbers, = (50 * 30) - (35 +40)
= 1500 - 75
= 1425
Average = 1425 /48 = 29.68.
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19. There were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were
increased by Rs.42 per day while the average expenditure per head diminished by Re 1. What was the original
expenditure of the mess?
A. Rs. 450
B. Rs. 320
C. Rs. 550
D. Rs. 420 (Answer)
Answer: Option D
Solution: Let the original average expenditure be Rs.x then, 42(x - 1) - 35x = 42.
=> 7x = 84
=> x = 12
Therefore original expenditure,
= Rs.(35 * 12)=Rs.420.
20. The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two
books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
A. Rs. 5, Rs.7.50
B. Rs. 8, Rs. 12
C. Rs. 10, Rs. 16 (Answer)
D. Rs. 12, Rs. 14
Answer: Option C
Solution: Total cost of 10 books = Rs. 120.
Total cost of 8 books = Rs. 94.
=> The cost of 2 books = Rs. 26.
Let the price of each book be x and y.
=> x + y = 26 ---------------- (1)
Given that the price of 1 book is 60% more than the other price
(160/100)y +y=26.
y(160/100+1) = 26.
y =(26*100)/260.
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Y = 10.
Substituting Y = 10 in (1) we get,
x + 10 = 26.
x = 16.
21. Nine persons went to a hotel for taking their meals. Eight of them spent Rs.12 each on their meals and the ninth
spent Rs.8 more than the average expenditure of all the nine. What was the total money spent by them.
A. Rs. 115
B. Rs. 116
C. Rs. 117 (Answer)
D. Rs. 118
Answer: Option C
Solution: Let the average expenditure of all the nine be RS. X.
Then, 12 * 8 + (X + 8) = 9X.
Therefore X = 13 Total money spent = 9X = RS.(9 * 13) = Rs.117
22. A cricketer scored some runs in his 21st innings, as a result, his average runs increased by 3. If the present average
run is 40, how many runs he scored in the final innings?
A. 103
B. 100 (Answer)
C. 85
D. 82
Answer: Option B
Solution: Let he scored X runs in final innings.
Now,
37 *20 +X = 40 *21
X = 840 -740 = 100.
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23. There are two sections A and B of a class, consisting of 36 and 44 students respectively. If the average weight of
section A is 40kg and that of section B is 35kg, find the average weight of the whole class.
A. 30 kg
B. 35 kg
C. 42.5 kg
D. 37.25 kg (Answer)
Answer: Option D
Solution: Total weight of (36 +44) Students,
= (36*40 +44*35)kg = 2980kg.
Therefore average weight of the whole class,
= (2980/80) kg.
24. The average weight of 47 balls is 4 g. if the weight of the bag (in which the balls are kept) be included; the calculated
average weight per ball increases by 0.3 g. What is the weight of the bag?
A. 14.8g
B. 14.4g
C. 15g
D. 18.6g
E. None of these (Answer)
Answer: Option E
Solution: Total weight of balls = 47*4 = 188 g;
Total increased weight = 0.3*47 = 14.1 g.
25. The average score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42, then find
the average for the last four matches.
A. 33.25
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B. 33.5
C. 34.25 (Answer)
D. 35
Answer: Option C
Solution: Total sum of last 4 matches,
= (10 * 38.9) - (6 * 42)
= 389 - 252 = 137
Average = 137 /4 = 34.25
=============================================================
1. 3 years ago the average of a family of 5 members was 17 years. A baby having been born, the average age of the
family is the same today. The present age of the baby is:
A. 1 years
B. 3/2 years
C. 2 years (Answer)
D. 3 years
Answer: Option C
Solution: Let age of the baby is x.
3 years ago total age of the family = 5 *17 = 85 years.
Total age of the 5 member at present time,
= 85 + 3*5 = 100 years
Total age of the family at present time including baby,
= 100 + X.
The average of the family including baby at present time,
= 17 years.
(100 +X)/6 = 17
100 +X = 102
X = 102 - 100 = 2 years.
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2. Of the three numbers, the first is twice the second and the second is twice the third. The average of the reciprocal of
the numbers is 7/72. The numbers are:
A. 36, 18, 9
B. 24, 12, 6 (Answer)
C. 20, 10, 5
D. 16, 8, 4
Answer: Option B
Solution: Let three numbers be x, y,z.
Given,
x =2y
=> x = 4z
=> y = 2z
=> z = z
The average of reciprocal numbers is 7/72.
[(1/x)+(1/y)+(1/z)]/3 = 7/72
=> (yz+xz+xy)/3xyz =7/72
=> (2z2+4z2+8z2)/(3*4z*2z*z)= 7/72.
=> (14z224z3)= 7/72
=> 504 =84z
z = 6
So, x = 4z = 4*6 = 24,
=> y = 2z = 2*6 = 12.
Thus the numbers are 24, 12, 6.
3. The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago
was 20 years. The present age of the husband is:
A. 35 years
B. 40 years (Answer)
C. 50 years
D. None of these
E. None of these
Answer: Option B
Solution: Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
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Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
4. In which year, the Forward Contracts (Regulation) Act was enacted in India?
A. 1950
B. 1952 (Answer)
C. 1962
D. 1975
Answer: Option B
5. The average salary of all the workers in a workshop is Rs. 8,000. The average salary of 7 technicians
is Rs. 12,000 and
the average salary of the rest is Rs. 6,000. The total number of workers in the workshop is:
A. 20
B. 21
C. 22
D. 23
Answer: Option B
Solution: Let the rest workers = x.
Now, According to question,
(7+x)*8000 = 12000*7 +6000x.
56000 +8000x = 84000+6000x.
2000x =28000.
x =14.
So total no of worker =14+7=21.
6. A student finds the average of 10 positive integers. Each integer contains two digits. By mistake, the boy interchanges
the digits of one number say ba for ab. Due to this, the average becomes 1.8 less than the previous one. What was the
difference of the two digits a and b?
A. 8
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B. 6
C. 2 (Answer)
D. 4
Answer: Option C
Solution: Let the original number be (10a + b).
After interchanging the digits, the new number becomes (10b + a).
The question states that the average of 10 numbers has become 1.8 less than the original average. Therefore, the sum
of the original 10 numbers will be (10*1.8 = 18_ more than the sum of the 10 numbers with the digits interchanged.
10a+b = 10b+a+18
9a - 9b =18
a - b= 2
7. The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then
the weight of B is:
A. 17 kg
B. 20 kg
C. 26 kg
D. 31 kg (Answer)
Answer: Option D
Solution: Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
Therefore B's weight = 31 kg.
8. The average age of A, B, C, D and E is 40 years. The average age of A and B is 35 years and the average of C and D is 42
years. Age of E is :
A. 48
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B. 46 (Answer)
C. 42
D. 45
Answer: Option B
Solution: A+B+C+D+E = 40*5 = 200
A+B = 35*2 = 70
C+D = 42*2 = 84
Therefore,
E = (A+B+C+D+E )-(A+B+C+D ) = 200-70-84 = 46 years.
9. 40% of the employees in a factory are workers. All the remaining employees are executives. The annual income of
each worker is Rs. 390. The annual income of each executive is Rs. 420. What is the average annual income of all the
employees in the factory together?
A. 390
B. 405
C. 408 (Answer)
D. 415
Answer: Option C
Solution: Let X be the number of employees.
We are given that 40% of the employees are workers. Now, 40% of X is (40/100)*X =0.4X.
Hence, the number of workers is 2X/5.
All the remaining employees are executives, so the number of executives equals,
(The number of Employees)-(The number of Workers),
= X-(2X/5)
=(3X/5)
The annual income of each worker is Rs. 390.
Hence, the total annual income of all the workers together is,
= (2X/5)*390 =156X.
Also, the annual income of each executive is Rs. 420. Hence, the total income of all the executives together is,
(3X/5)*420 =252X
Hence, the total income of the employees is,
= 156X +252X =408X.
The average income of all the employees together equals,
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10. Which among the following banks has launched the "Tatkal", scheme that enables the people to transfer money to
their families in their native towns and villages without actually opening an account?
A. State Bank of India
B. Bank of India (Answer)
C. Canara Bank
D. Union Bank of India
Answer: Option B
11. The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
A. 0
B. 1
C. 10
D. 19 (Answer)
E. None of these
Answer: Option D
Solution: Average of 20 numbers = 0.
Therefore Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
12. The average of 50 numbers is 30. If two numbers, 35 and 40 are discarded, then the average of the remaining
numbers is nearly:
A. 28.32
B. 29.68 (Answer)
C. 28.78
D. 29.27
Answer: Option B
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Solution: Total sum of 48 numbers,
= (50 × 30) – (35 +40)
= 1500 – 75
= 1425
Average = 1425/48 = 29.68The average score of a cricketer for ten matches is 38.9 runs.
13. In a set of three numbers, the average of first two numbers is 2, the average of the last two numbers is 3, and the
average of the first and the last numbers is 4. What is the average of three numbers?
A. 2
B. 2.5
C. 3 (Answer)
D. 3.5
Answer: Option C
Solution: Let the three numbers be x, y, and z. We are given that
(x+y)/2 =2
(y+z)/2 =3
(x+z)/2 =4
Adding three equations,
(x+y)/2+(y+z)/2+(x+z)/2 =2+3+4
x+y+z = 9
The average of the three numbers is,
(x+y+z)/3 = 9/3 = 3.
14. When was SEBI established?
A. 1990
B. 1991
C. 1992 (Answer)
D. 1984
Answer: Option C
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15. The average of first five multiples of 3 is:
A. 9 (Answer)
B. 10
C. 8
D. 11
Solution: First five multiples of three are: 3,6,9,12,15.
Average = (3+6+9+12+15)/3 = 9.
Alternatively,
Average = (3 +15)/2 = 9
16. The Chameli Devi Jain Award is given for an outstanding woman ---------?
A. Scientist
B. Reporter (Answer)
C. Player
D. Teacher
Answer: Option B
17. A man started his journey from Lucknow to Kolkata, which is 200 km, at the speed of 40 kmph then he went to
Banglore which is 300 km, at the speed of 20 kmph. Further he went to Ahmedabad which is 500 km, at the speed of 10
kmph. The average speed of the man is :
A. 14(2/7) kmph (Answer)
B. 14(5/7) Kmph
C. 15.6 kmph
D. 16.1 kmph
Solution: Average speed,
= (Total distance /Total time)
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= [(200+300+500)/{(200/40)+(300/20)+(500/10)}]
= 1000/70
= 14(2/7) kmph.
18. Which of the following is not a primary function of a Bank?
A. Granting Loans
B. Collecting Cheques/Drafts customers
C. Facilitating import of goods (Answer)
D. Issuing Bank Drafts
Answer: Option C
19. Weight of new person = (65 + 20) kg = 85 kg.The average monthly income of P and Q is Rs. 5050. The average
monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P
is:
A. 3500
B. 4000 (Answer)
C. 4050
D. 5000
E. None of these
Answer: Option B
Solution: Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
Therefore P's monthly income = Rs. 4000.
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20. Expand REDP. It is an initiative by NABARD.
A. Rural Employment Development Programme
B. Rural entrepreneurship Development Planning
C. Rural Employment Development Planning
D. Rural Entrepreneurship Development Programme (Answer)
Answer: Option D
21. There are three categories of jobs A, B and C. The average salary of the student who got the job of A and B categories
is 26 lakh per annum. The average salary of the students who got the job of B and C category is 44 lakh per annum and
the average salary of those students who got the job of A and C categories is 34 lakh per annum. The most appropriate
(or closet) range of average salary of all the three categories (if it is known that each student gets only one category of
jobs i.e. , A, B and C):
A. lies between 30 and 44 (Answer)
B. lies between 28 and 34
C. lies between 34 and 44
D. lies between 27 and 44
E. None of these
Solution: Let the number of students who got the job of A, B and C categories is a, b and c respectively,
Then the total salary,
= [{26(a+b)+44(b+c)+34(c+a)}/2(a+b+c)]
= [(60a+70b+78c)/2(a+b+c)]
= [30(a+b+c)+(5b+9c)]/(a+b+c)
= 30 + some positive value
Thus, the minimum salary must be Rs. 30 lakh and the maximum salary can not exceed 44, which is the highest of the
three.
22. Saumitra Chaudhuri committee has been appointed to recommend revisions to :
A. Wholesale Price Index
Page 36
B. Consumer Price Index
C. Index of Industrial Production (Answer)
D. Housing Develoment Index
Answer: Option C
23. A man has 'n' magical eggs whose average weight is 'k' gm. Each of the 'n' eggs produces 'n' eggs next day such that
the average weight of 'n' eggs produced is same as that of the parental egg for each 'n' groups individually i.e. each egg
produces 'n' eggs of next generation and average weight of all the 'n' eggs of next generation is same as the weight of
the mother egg. This process is continued without any change in pattern. What is the total weight of all the eggs of rth
generation, where the initial number of eggs with man are considered as the eggs of first generation.
A. rnk
B. rnk
C. nkr
D. nrk
E. None of these
Answer: Option D
Solution: The weight is increasing in form of GP so the total weight of eggs in the end of rth will be nrk.
24. The mean weight of 100 students in a class is 46 kg. The mean weight of boys is 50 and of girls is 40 kg. Therefore,
the number of boys is:
A. 50
B. 60 (Answer)
C. 70
D. 65
Answer: Option B
Solution: Let number of boys are x and then number of girls = (100-x).
Thus,
50x+(100-x)*40 = 46*100
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→ x = 60.
Number of boys = 60.
25. The average monthly salary of 12 workers and 3 managers in a factory was Rs. 600. When one of the manager whose
salary was Rs. 720, was replaced with a new manager, then the average salary of the team went down to 580. What is
the salary of the new manager?
A. 640
B. 690
C. 420 (Answer)
D. 570
Answer: Option C
Solution: The total salary amount = 15 × 600 = 9000
The salary of the exiting manager = 720.
Therefore, the salary of 12 workers and the remaining 2 managers,
= 9000−720 = 8280
When a new manager joins, the new average salary drops to Rs.580 for the total team of 15 of them.
The total salary for the 15 people i.e., 12 workers, 2 old managers and 1 new manager =580×15 =8700
Therefore, the salary of the new manager is,
9000 - 8700 = 300 less than that of the old manager who left the company, which is equal to 720 - 300 = 420.
Alternatively,
The average salary dropped by Rs.20 for 15 of them.
Therefore, the overall salary has dropped by 15×20=300.
Therefore, the new manager's salary should be Rs.300 less than that of the old manager,
= 720−300 =420.
26. The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two
books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
A. Rs. 5, Rs.7.50
B. Rs. 8, Rs. 12
C. Rs. 16, Rs. 10(Answer)
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D. Rs. 12, Rs. 14
Answer: Option C
Solution: Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
=> The cost of 2 books = Rs. 26
Let the price of each book be x and y.
=> x + y = 26 ---------------- (1)
(160/100)y+y =26
On Solving for y, we get
y = 10.
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16.
So the price of each book is Rs. 16 and Rs. 10 respectively.
27. A commercial bank will launch a medium term note (MTN) programme to
A. Provide loans
B. Purchase shares
C. Sell Equity
D. Raise Funds (Answer)
Answer: Option D
28. HDFC bank has been named among 50 most valuable banks in 2014. It has got 45th rank. Wells Fargo & Co. has got
first rank in this list. This bank belongs to which country?
A. UK
B. France
C. European Union
D. USA (Answer)
Answer: Option D
Page 39
29. Who provides refinance facilities to RRBs?
A. SIDBI
B. NABARD (Answer)
C. RBI
D. Government of India
Answer: Option B
30. The difference between the outflow and inflow of foreign currency is known as
A. Balance of Payments
B. Foreign Exchange Reserves
C. Current Account Deficit (Answer)
D. Fiscal Deficit
Answer: Option C
31. There are two sections A and B of a class, consisting of 36 and 44 students' respectively. If the average weight of
section A is 40kg and that of section B is 35kg, find the average weight of the whole class.
A. 30 kg
B. 35 kg
C. 42.5 kg
D. 37.25 kg (Answer)
Answer: Option D
Solution: The otal weight of (36+44) Students of A and B,
= (36*40 +44*35)kg = 2980kg.
Therefore average weight of the whole class,
= (2980/80) kg.
Therefore average weight = 37.25kg.
Page 40
32. A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale
must he have in the sixth month so that he gets an average sale of Rs. 6500?
A. Rs. 4991 (Answer)
B. Rs. 5991
C. Rs. 6001
D. Rs. 6991
E. None of these Solution: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Therefore Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
33. If the average for the first six matches is 42, then find the average for the last four matches.
A. 33.25
B. 33.5
C. 34.25 (Answer)
D. 35
Answer: Option C
Solution: Total sum of last 4 matches,
= (10* 38.9) - (6* 42)
= 389 - 252 = 137
Average = 137/4 = 34.25
34. Distance between two stations A and B is 778km. A train covers the journey from A to B at 84 km per hour and
returns back to A with a uniform speed of 56 km per hour. Find the average speed of train during the whole journey.
A. 60 km/hr
B. 30.5 km/hr
C. 57 km/hr
D. 67.2 km/hr (Answer)
Page 41
Answer: Option D
Solution: The required average speed given by the formula,
Average speed =[2xy/(x+y)]km/hr.
Where,
x = 84 kmph.
y = 56 kmph.
Average speed, = [(2*84*56)/(84+56)]
= 67.2 kmph.
35. A Batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after
17th inning.
A. 40
B. 39 (Answer)
C. 52
D. 55
Answer: Option B
Solution: Let the average after 17th innings = x.
Then average after 16th innings = (x-3).
Therefore 16*(x-3) + 87 = 17x.
Therefore x = 39.
36. In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Arun and he
thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater
than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
A. 67 kg. (Answer)
B. 68 kg.
C. 69 kg.
D. Data inadequate
Solution: Let Arun's weight by X kg.
According to Arun,
65< X<72
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According to Arun's brother,
60< X<70.
According to Arun's mother,
X≤68
The values satisfying all the above conditions are 66, 67 and 68.
Required average,
= (66+67+68=201)/3 = 67 kg.
37. In 2011, the arithmetic mean of the annual incomes of Ramesh and Suresh was Rs. 3800. The arithmetic mean of the
annual incomes of Suresh and Pratap was Rs. 4800, and the arithmetic mean of the annual incomes of Pratap and
Ramesh was Rs. 5800. What is the arithmetic mean of the incomes of the three?
A. Rs. 4000
B. Rs. 4200
C. Rs. 4400
D. Rs. 4800 (Answer)
Answer: Option D
Solution: Let a, b, and c be the annual incomes of Ramesh, Suresh, and Pratap, respectively.
Now, we are given that
The arithmetic mean of the annual incomes of Ramesh and Suresh was Rs. 3800.
Hence,
(a+b)/2 =3800 => a+b = 2*3800 =7600.
The arithmetic mean of the annual incomes of Suresh and Pratap was Rs. 4800.
Hence,
(b+c)/2 =4800
b+c = 2*4800 =9600.
The arithmetic mean of the annual incomes of Pratap and Ramesh was Rs. 5800.
Hence,
(c+a)/2 =5800 c+a = 2*5800=11,600
Adding these three equations yields:
(a+b)+(b+c)+(c+a)=7600 +9600 +11,600
2a+2b+2c =28,800
a+b+c =14,400
The average of the incomes of the three equals the sum of the incomes divided by 3,
(a+b+c)/3 =14,400 /3 = Rs. 4800
Page 43
38. The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65
kg. What might be the weight of the new person?
A. 76 kg
B. 76.5 kg
C. 85 kg (Answer)
D. Data inadequate
E. None of these
Answer: Option C
Solution: Total weight increased = (8 x 2.5) kg = 20 kg.
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Excellent math mcqs for general test